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        <title>courses:b3b33kui:kuimaze:2_mdpmaze - old revision restored (2023/03/21 11:20)</title>
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        <description>MDPMaze

Příklad použití

Vytvořme mapu jednoduchého bludiště:



&gt;&gt;&gt; EMPTY = (255, 255, 255)
&gt;&gt;&gt; WALL = (0, 0, 0)
&gt;&gt;&gt; GOAL = (255, 0, 0)
&gt;&gt;&gt; START = (0, 0, 255)

&gt;&gt;&gt; MAP1 = ((EMPTY, START, EMPTY, EMPTY, EMPTY),
            (EMPTY, WALL,  WALL,  WALL,  EMPTY),
            (EMPTY, EMPTY, EMPTY, WALL,  GOAL))</description>
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        <description>Lecture materials

Timetable

The course takes place every Monday (B0B17MTB) and every Wednesday (BE0B17MTB) from 16:15 to 18:30 in the room T2: A3-412 in Dejvice (unless stated otherwise on the title page).

Semester schedule: [ See slide 6 and 7...]

List of useful MATLAB functions</description>
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        <title>courses:pri-bootcamp:solutions:day3 - [Úkol 1] </title>
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        <description>Den 3

Opakování for-cyklu

Úkol 1



# Vasek

a = int(input(&quot;Zadejte diferenci: &quot;))
b = int(input(&quot;Zadejte prvni clen: &quot;))

for i in range(b,a*20+b,a):
    print(i)



----------

Úkol 2



# riskoana

n = int(input(&quot;Zadejte hodnost: &quot;))
for i in range(n-1): #jen do předposlední řady
    for j in range(n-1): #poslední sloupec budeme řešit odděleně
        if i == j:
            print(&quot;1&quot;, end=&quot;, &quot;)
        else:
            print(&quot;0&quot;, end=&quot;, &quot;)
    print(&quot;0&quot;) #poslední sloupec dá vždycky 0
for …</description>
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        <title>courses:pri-bootcamp:03 - [Úkol 1] </title>
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        <description>Den 3

Úkoly na opakování for-cyklu

Úkol 1

Aritmetická posloupnost je posloupnost čísel, která má stálý rozdíl sousední členů. Tomuto rozdílu říkáme diference. Například posloupnost
0 5 10 15 20 25 30 ...

má diferenci 5. 
Zadejte diferenci: 7
0 7 14 21 28 35 42 49 56 63 70 77 84 91 98 105 112 119 126 133$1 \cdot 2^4 + 0 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 0 \cdot 2^0 = 16 + 4 = 20$$&lt;a; b)$$\pi$$&lt;a, b&gt;$$\pi$$ \pi = 4 \left( 1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \frac{1}{9} - \frac{…</description>
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        <title>courses:pri-bootcamp:solutions:day2 - [Úkol 0] </title>
        <link>https://cw.fel.cvut.cz/b222/courses/pri-bootcamp/solutions/day2?rev=1695134232&amp;do=diff</link>
        <description>Den 2

Opakování



# Vojta
# revize riskoana
utrata = int(input(&quot;Zadejte vasi utratu: &quot;))
if (utrata &gt;= 0):
    padesat = utrata//50
    zbytek = utrata%50
    dvacet = zbytek//20
    zbytek = zbytek%20
    deset = zbytek//10
    zbytek = zbytek%10
    pet = zbytek//5
    zbytek = zbytek%5
    dva = zbytek//2
    zbytek = zbytek%2
    jedna = zbytek
    celkem = padesat+dvacet+deset+pet+dva+jedna
    print(&quot;Celkem je potreba &quot; + str(celkem) + &quot; minci&quot;)
    print(&quot;Pocet minci o hodnote 50 Kc:&quot;, …</description>
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